Question

If ‘I’ is the intensity of the solar radiation at a distance ‘x’ from the surface of the Sun, and if ‘A’ is the surface area of a solar flat plate collector placed at x, with its surface directly facing the sun, and with ‘I’ and ‘A’ given in SI units, the power falling on the collector is given by _________ Watts

Answer 1

Power can be given as

P = I*A

Where, I is the intensity of source

and A is the Area of surface facing

Intensity and distance X relation given as below.

$\frac{1}{X^{2} }$

Hope it helps

Thanks

With Regards

Answer 2

Hello friend,

◆ Solar constant-

It is the rate at which solar energy reaches the earth's surface from the sun.

◆ Answer-

the power falling on the collector is given by 4πx^2.I Watts.

◆ Explaination-

Suppose,

I = intensity of solar radiation

x = distance from sun suraface

A = surface area of solar collector

P = Power falling on the collector

Power falling on solar flat plate collector is calculated by-

P = 4πx^2.I

Hope this helps...