Question

If Ā=i+j and B = i- j. The value of (A+B).(A-B) is​

Answer 1

Answer:

2

Explanation:

When we calculate the magnitude of A we get $\sqrt{2}$

When we calculate the magnitude of B we get 0

A + B  ==>  R = $\sqrt{A^{2} + B^{2} + 2ABcos(theta)}$ =  $\sqrt{2}$

A - B ==>  R = $\sqrt{A^{2} + B^{2} - 2ABcos(theta)}$ = $\sqrt{2}$

(A + B) . (A - B)

($\sqrt{2}$) . ($\sqrt{2}$)

2

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