Question

If I make a solution by adding 83 grams then f sodium hydroxide to make 750mL of solution, what is the molarity of sodium hydroxide in this solution?

Answer 1

Answer:

m=83g

M.M. of NaOH=40g

V=750mL=0.75L

⇒n=m/M.M.

n=2.075 mol

As, M=n/V

=2.075/0.75≈2.76 mol/L

Therefore, Molarity is 2.76M