Question

if i p is a root of the quadratic equation x^2+px(1-p)

Answer 1

Hi Friend !!!

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If p is root then
put x = p

x²+px(1-p) = p²+p×p(1-p)

= >p²+p²(1-p) = 0

= >p²+p²-p³ = 0


= > 2p²-p³ = 0

=>p²(2-p) = 0

=> 2-p = 0

=> p = 2

hope it helps u

Answer 2

HELLO......FRIEND!!

THE ANSWER IS HERE,

p is the root of the quadratic equation.

So, x=p.

$= > \: {x}^{2} + px(1 - p) = 0$

$= > \: {p}^{2} + p(p)(1 - p) = 0$

$= > \: {p}^{2} + {p}^{2} (1 - p) = 0$

$= > \: {p}^{2} (1 + 1 - p) = 0$

$= > \: {p}^{2} (2 - p) = 0$

So, P=0 & P=2.

:-)Hope it helps u.