Question

if i reduce radius by half and I double the length ..what will be the young modulus of the material​

Answer 1

Answer:

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Answer 2

Answer:

Y=

AΔL

Fl

Y=

πr

2

Δl

FL

Y

2

=

π(Y/2)

2

F

Δl

(L/2)

Y

2

=2Y

Explanation:

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