if I travel from Mumbai to Pune for 150 km in 2 and a hafe while coming returning from Pune to mumbai 180 km for 3and a half hours calculat average velocity
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Let V1 be the velocity while going to Pune and V2 be the velocity while returning from Pune
while going to Pune Time taken (T1)=2½ hrs
Distance (D1)=150 km
V1=D1/T1
V1=150/2½
V1=150/(5/4)
V1=(150×5)/4
V1=750/4
V1=187.5 km/hr
while returning from Pune
Time taken (T2) =3½hrs
Distance (D2)= 180 km
V2=D2/T2
V2=180/3½
V2=180/(7/2)
V2=(180×2)/7
V2=360/7
V2=51.428
V2=51.43km/hr
Avg velocity = (V1 +V2)/2
Avg velocity = (187.5+51.43)/2
Avg velocity = 238.93/2
Avg velocity = 119.465km/hr
Hope it HELPS
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