Question

If I want to find the sum of the number of jawbreakers I give 50 people, and I give the first person one, the second person 4, third person 7, etc.
what is n? (the number of people that get jawbreakers)

Answer 1

Answer:

The question demands the value of n, which is obviously 50. I presume you would have misstated your question, so I am going to solve the whole problem.

Step-by-step explanation:

There are 50 people, and you give the first person 1 jawbreaker, the second person 4 jawbreakers, the third person 7 jawbreakers and so on....

The scenario can be represented as an AP in the form of

1,4,7.......a₅₀

where a=1, d=3 and n=50

We know aₙ=a+(n-1)d

So, a₅₀ = 1 + ( 50 - 1 ) 3 = 1+49(3)=1+147=148

We also know that the sum of n terms,

Sₙ = n/2 (a+l)

where l is the last term.

So,

S₅₀ = 50/2 (1+148)

=25*149=3725

The number of jawbreakers that get distributed is 3725.

Hope this helps!

<3