if i²=-1,then the value of 200 summasion n=1for i to the power of n is? options are 50,-50,0 and 100
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2
the answer is 0.there are only four things repeated I.e.i,-1,-i,and 1 and sum of all these are zero.
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8
i¹ + i² + i³ + i⁴ +.........iⁿ
where n =200
we Know,
i² = -1
i³ = i
i⁴ = 1
add I , i² , i³, i⁴ then value =0
he nce , we can say that
( i +i² + i³ + i⁴) ........( i^(n-3) +i^(n-2)+i^(n-1)+iⁿ)
0 + 0 +0 .......0= 0
where n =200
we Know,
i² = -1
i³ = i
i⁴ = 1
add I , i² , i³, i⁴ then value =0
he nce , we can say that
( i +i² + i³ + i⁴) ........( i^(n-3) +i^(n-2)+i^(n-1)+iⁿ)
0 + 0 +0 .......0= 0
vickeydey:
plss explain it properly
this is enough for solutions ,
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