Question

If icap and jcap are unit vectors along mutually perpendicular directions then magnitude of icap-jcap

Answer 1

i^ - j^ is a unit vector.

Magnitude of a vector is given by whole root of coefficient of i^ squared + coefficient of j^ squared + coefficient of k^ squared

So,
Magnitude of i^ - j^ = √1^2 + (-1)^2
= whole root of 1+1
= √2

Therefore, magnitude of i^-j^ = √2.

Answer 2

Answer: since î and j^ are mutually perpendicular to wash other then angle between both the vectors will be 90°

Now î= 1( because it is unit vector )

And j^ = -1

Now |[î-j^]|= √(1)²+(-1)²+ cos90°

= √ 1+1+0. (Because cos90°=0)

= √2

Hence, magnitude of î-j^ is √2