Question

if if 12.6 gram of NaHCO3 are added to 30.0 gram of CH3COOH solution the Residue is found to weigh 36.0g what is the mass of CO2 released in the reaction?

Answer 1

Answer:- mass of carbon dioxide released in the reaction is 6.6 g.

Solution:- The chemical equation for the given problem is:

$NaHCO_3+CH_3COOH\rightarrow CH_3COONa+H_2O+CO_2$

From this equation, both the reactants react in 1:1 mol ratio to produce 1 mol of carbon dioxide gas.

moles of $NaHCO_3$ = $12.6g(\frac{1mol}{84g})$

= 0.15 mol

moles of $CH_3COOH$ = $30g(\frac{1mol}{60g})$

= 0.5 mol

From the moles, $NaHCO_3$ is limiting and so 0.15 moles of carbon dioxide would. molar mass of carbon dioxide is 44.

mass of carbon dioxide formed = 0.15 * 44 = 6.6 g

Another method:- Chemical reactions obey law of conservation of mass. From this law, "mass is neither created nor destroyed." Sum of masses of reactants must be equal to the sum of masses of products.

Sum of mass of reactants = 12.6 + 30.0 = 42.6 g

mass of residue = 36.0 g

sum of mass of reactants = mass of residue + mass of carbon dioxide gas

mass of carbon dioxide gas = sum of mass of reactants - mass of residue

mass of carbon dioxide gas = 42.6 - 36.0 = 6.6 g

Answer 2

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