If if a and b are the zeros of the polynomial 2ysquare +7y+5 write the value a+b+ab
Answers
Step-by-step explanation:
Given -
- α and β are zeroes of polynomial p(y) = 2y² + 7y + 5
To Find -
- Value of α + β + αβ
Method 1 :-
→ 2y² + 7y + 5
→ 2y² + 2y + 5y + 5
→ 2y(y + 1) + 5(y + 1)
→ (2y + 5)(y + 1)
Zeroes are -
→ 2y + 5 = 0 and y + 1 = 0
→ y = -5/2 and y = -1
Then,
The value of α + β + αβ is
→ -5/2 + (-1) + (-5/2) × (-1)
→ -5/2 - 1 + 5/2
→ -5 - 2 + 5/2
→ -2/2
→ -1
Method 2 :-
As we know that :-
- α + β = -b/a
→ α + β = -(7)/2
→ α + β = -7/2
And
- αβ = c/a
→ αβ = 5/2
Then,
The value of α + β + αβ is
→ -7/2 + 5/2
→ -7 + 5/2
→ -2/2
→ -1
Hence,
The value of α + β + αβ is -1
Given:
- We have been given that a and b are the zeroes of the polynomial 2y^2 + 7y + 5.
To Find:
- We need to find the value of a + b + ab.
Solution:
We have been given a polynomial 2y^2 + 7y + 5.
Here, a = 2, b = 7 and c = 5.
As it is given that a and b are two zeroes,
So, sum of zeroes(a + b)
= -b/a
= -7/2___(1)
Product of zeroes(ab)
= c/a
= 5/2___(2)
Now we need to find the value of a + b + ab,
So we have,
a + b + ab = (a + b) + ab
Substituting the values from equation 1 and 2, we get,
(-7/2) + (5/2)
= (-7 + 5)/2
= -2/2
= -1
Therefore, the value of a + b + ab is -1.