Question

If if alpha and beta are the zeros of the polynomial 6 y squared minus 7 y + 2 find the quadratic polynomial whose zeros are one by alpha and one by beta

Answer 1

Step-by-step explanation:

............................

Answer 2

Answer:

Step-by-step explanation:

Alpha + beta = 7/6

Alpha × beta = 1/3

If one by alpha and one by beta are the zeroes of required f(x)

So

1/alpha +1/beta=alpha+beta/alphabeta

=7/6by 1/3

=7/6×3/1

=21/6

Now ,

1/alpha×1/beta=1/alphabeta

=1by 1/3

=1×3/1

=3

So , required f(x)

=x'2-(1/alpha+1/beta)x+1/alpha×1/beta

=x'2-21/6x+3

=6x'2-21x+18