if if alpha, beta and gamma are zeroes of the the polynomial p(x) = 2x^2-7x+3 , then find the value of
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2x²-7x+3
2x²-6x-1x+3
2x(x-3)-1(x-3)
(2x-1)(x-3)
alpha
2x-1=0
x=1/2
beta
x-3=0
x=3
alpha³+beta³=(1/2)³+3³
1/8+27
2157/8
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