If if area of Rhombus be 24 cm square and one of its diagonals is 4 cm find the perimeter of rhombus
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Answer:
first diagonal be 4 cm
second be X
area of rhombus=
4 X x = 24 X 2
x=12
one side=
4x4 +12x12 =x
x=✓160
perimeter=4x✓160=16✓10
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