Chemistry, asked by yedeshekhar2, 8 months ago

If ∆If/m for glucose is 1.86 then ∆If/m for HCL is.​

Answers

Answered by anjalinagwani92
0

Answer:

3.72

Explanation:

depression in freezing point per m will be kf×i

where i is vant hoff factor

for glucose its value is 1 as it is non electrolyte while for HCl its value will be 2

so tf per m will become twice

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