Question

if if the sum of three consecutive number is 101 then find the greater one

Answer 1

Hii Mate here is your answer,

Let x is the smallest number.

Given consecutive means differ by 1.

So, other numbers are

x+1 and x+1+1 = x+2

A/Q = x +(x+1) + (x+2) = 101 .....Now solve it

x+x+1+x+2 = 101

3x +3 = 101

3x = 101 - 3

3x = 98

X = 98/3 = 32.66 (Approx)

So the largest number is x + 2 = 32.66+2 = 34.66 (Ans)

☆☆☆☆HOPE THIS HELPS YOU A LOT☆☆☆☆

Answer 2

sum of three consecutive number =101
find greater one...
$\frac{101}{3} = 33. ....\: something$
32, 34, 35...... 35 is the greater one