If if the two positive number is 108 and
the difference of those number is 8 then the find those numbers
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Answered by
0
the sum of the numbers=108
their difference =8
Number of positive numbers=2
since their difference is 8 so 108-8=100
the two numbers are =100/2=50
1st number=50
2nd number = 50+8 =58
their difference =8
Number of positive numbers=2
since their difference is 8 so 108-8=100
the two numbers are =100/2=50
1st number=50
2nd number = 50+8 =58
Answered by
0
Let two numbers be x and y
According to question
x + y = 108
x - y = 8 …………[1]
Add both the equations
x + y + x - y = 108 + 8
2x = 116
x = 58
If x = 58 then from equation [1] y = 58 - 8 = 58
The two numbers are 58 and 50
According to question
x + y = 108
x - y = 8 …………[1]
Add both the equations
x + y + x - y = 108 + 8
2x = 116
x = 58
If x = 58 then from equation [1] y = 58 - 8 = 58
The two numbers are 58 and 50
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