Question

.If IL = 221.5 and IF = 222, find IP.


plzz ans fast imp....​

Answer 1

Answer:

There are 8 bits in total for host address. Out of which half of them are assigned to A. So 2^8/2 host addresses are for A.

So 0 0000000 to 0 1111111.

Remaining is 2^7. That has to be equally divided among BCDE.

2^7/4 =2^5.

Hence 5 bits.

B: 1 00 00000 to 1 00 11111

C: 1 01 00000 to 1 01 11111

D: 1 10 00000 to 1 10 11111

E: 1 11 00000 to 1 11 11111

The 1st and last addresses of every set are not assigna

Explanation:

Answer 2

Answer:

Explanation:IF = √IL ×IP

IF=222

IP=221.5

IF=√IL×IP

222=√221.5×IP

(222 ×222) ÷221.5=IP