Question

If in 1967 and 1969 a worker received 10% more in salary each year than he did the
previous year, how much more did he receive in
1969 than in 1967?

Answer 1

Let x be the amount he received in 1967

Find the amount he received in 1968 in term of x:

10% increased = 0.1x

Salary after increase = x + 0.1x = 1.1x

Find the amount he received in 1969:

10% increased = 0.1 x 1.1x = 0.11x

Salary after increase =  1.1x + 0.11x = 1.21x

Find the difference between 1967 and 1969:

Difference = 1.21x - 1x = 0.21x

Difference in percentage = 0.21x/x x 100 = 21%

Answer: He received 21% more in 1969 than in 1967.