if in 2 triangle PQR and triangle ABC AB/QR=BC/PR=CA/PQ, then
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(a) Given, in two Δ ABC and Δ PQR, AB/QR = BC/PR = CA/PQ
which shows that sides of one triangle are proportional to the side of the other triangle, then their corresponding angles are also equal, so by SSS similarity, triangles are similar.
i.e., Δ CAB ∼ Δ PQR
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