Math, asked by shannoshaikh07786, 3 months ago

If in a 1 km race. A
defeats B by 200 m,
and in a 500 m race.
B defeats C by 200
m, then by how
many metres would
A defeat C in a 200
race, assuming
that A, B and C
perform exactly the
in all the
races?​

Answers

Answered by anjali1910639
2

Answer:

answer is 11.11

Step-by-step explanation:

When A runs 200 m

S runs 180 m

N runs 160 m

When S run 100 m, N will run=100×

180

160

=88.89

i.e S will beat N by (100−88.89)=11.11 m

Answered by creativevishnu4
2

Answer:

120m

Step-by-step explanation:

1st case- A and B in 1000m race.

A defeats B by 200m in 1000m race.

So, A defeats B by (200/5)m in (1000/5)m race.

Means, A defeats B by 40m in 200m race.

2nd case-B and C in 500 m race.

B defeats C by 200m in 500m race.

So, B defeats C by 80m in 200m race.

Final case - A,B,C in 200 m race.

Now combine our before conclusions. So,

A defeats B by 40m and B defeats C by 80m in 200m race.

That's why, A defeats C by (40+80) =120m in 200m race.

Thank You

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