Math, asked by gauravsolat3, 2 months ago

 If in a ∆ABC, m<A = 42° and m<B = π/6 radian, then the m<C =​

Answers

Answered by lspfdnr
0

Answer:

It is given, In △ABC, 3∠A=4∠B=6∠C.

⇒ Let x=3∠A=4∠B=6∠C

⇒answer will get 40

=40

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