if in a box there are 3 blue balls 5 red balls, 2 green balls and one ball is drawn at random, what is the probability of getting
1.a blue ball
2.a green ball
3.not a red ball
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2
Answer:
Step-by-step explanation:
1:A BLUE BALL:3/10
2:A GREEN BALL:2/10=1/5
3:NOT ARED BALL:5/10=1/2 (10-5=5).
DrishtyKashyap:
thanks for the answer but last was not a red ball
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