Question

If in a Cartesian Plane , a convex lens is placed at the origin and a light source is placed at a point (-f/3 , 0 ) where f is the focal length of the lens then
See the attached image
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Answer 1

Answer:

For image formed by refraction through the lens,

v

1

−

u

1

=

f

1

⟹

v

1

−

−2

1

=

1.5

1

⟹v=6m

Magnification M=

u

v

=

−2

6

=−3

Hence image is formed 0.3 m below the axis.

From the figure,

x=6−d

& tanθ=

x

0.3

⟹x=1m

⟹d=5m

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Answer 2

Answer:

Here is ur answer....

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