if in a circuit the resistance is doubled and the potential difference remains same how does the current change derive this using Ohm's law.
pls give me proper answer
Answers
Answered by
0
Answer:
since V = IR
V/I = R
If resistance is doubled then current is halved.
Answered by
0
Answer:
Explanation:
According to Ohm's law
V = IR
I = V/R
according to condition
R' = 2R
so
I' = V/R'
I' = V/2R
I' = I/2
hence current will be reduced by half.
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