if in a circuit v=200 and I=5 then how many 100 waat bulbs can be connected in parallel
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Resistance of the 220V, 100W bulb is given by
R= V²/P =220²/100
=484Ω
Thus, when connected in series, total resistance Rs =484+484Ω
=968Ω
Power drawn in case of series combination,Ps
= V²/Rs = 220²/968
=50W
When connected in parallel, total resistance Rp
= 484/2Ω
=242Ω
Power drawn in case of series combination,P p
=V²/Rp = 220²/242
=200W
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