If in a class of 50 students, 10 play basket ball but not cricket, 10 play cricket but not basket ball and 15 play neither cricket nor basketball, then find the number of students playing both cricket and basketball.
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Step-by-step explanation:
Let A and B represents the students play cricket and football respectively.
Let x be the percentage of students play neither cricket nor football.
Given:-
n(A∩B)=10
n(A)=50
n(B)=40
Now,
n(A)+n(B)+x−n(A∩B)=100
⇒50+40+x−10=100
⇒x=110−90=20
Hence 20% students play neither cricket not foot ball
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