Question

if in a code white is written as xgjsf then how is black written in that code?

Answer 1

Explanation:

In order to crack this problem it is required to alphabets with their correct number.

A=1, B=2, C=3, D=4, E=5, F=6, G=7, H=8, I=9, J=10, K=11, L=12, M=13, N=14, O=15, P=16, Q=17, R=18, S=19, T=20, U=21, V=22, W=23, X=24, Y=25, Z=26

Now, WHITE ie, 23 8 9 20 5 is written as XGJSF ie, 24 7 10 19 6.

We can see that the series goes like +1, -1, +1, .....

Therefore,

BLACK ie, 2 12 1 3 11 can be written as 3 11 2 2 12 ie, ckbbl

Answer 2

Answer:

CKBBL

Explanation:

If in a code white is written as xgjsf then how is black written in that code?

Lets compare

WHITE    XGISF

W  -->  X   ( X is next letter to W)

H  -->   G   ( G is  letter before H)

I  -->   J      ( J is next letter to I)

T  -->   S    ( S is  letter before T)

E  -->  F     ( F is next letter to E)

we can notice here alphabets placed at odd positions are incremented by 1

and promoted to next alphabet

While alphabets at even position are decreased by 1 and demoted to one alphabet before

B  -->  C   ( C is next letter to B)

L  -->   K   ( K is  letter before L)

A -->   B      ( B is next letter to A )

C  -->   B    ( B is  letter before C)

K  -->  L     ( L is next letter to K)

Black will be codes as  CKBBL