If in a Coolidge tube, the electrons are accelerated by a potential difference V, what will be the minimum wavelength of the x-rays produced?
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Answer:Potential difference by which the electron is accelerated =60 kV=60000 V
So, energy of electron E=60000 eV
Minimum wavelength of X-ray λ=
E
hc
⟹ λ=
E(in eV)
12420
A
o
=
60000
12420
=0.21 A
o
Explanation:
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