Question

if in a cubic closed packed structure, atoms A are un ccp, ateaus B are in all octahedral voids and atoms C are in 25% tetrahedral . voids. Correct formula of the compound will be )​

Answer 1

Answer:

Since A forms close packed arrangement,

Number of atoms A in a unit cell = 4

B occupies one-fourth of tetrahedral voids,

Number of atoms B in a unit cell =

4

1

×8=2

C occupies half of octahedral voids,

Number of atoms C in a unit cell =

2

1

×4=2

Therefore, the formula of the compound is A

4

B

2

C

2

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