if in a cylinder radius is doubled and height is halved, then what is the percent change in curved surface area and volume?
Answers
Answered by
89
Hi,
1) Dimensions of the cylinder
radius = r
Height = h
i ) curved surface area
(CSA) = 2πrh----( 1 )
ii ) volume (v) = πr² h ---( 2 )
2 ) if radius doubled and radius
halved then new cylinder
dimensions are
Radius ( R ) = 2r
Height ( H ) = h /2
New CSA = 2 × π × ( 2r ) × h / 2
= 2πrh
Therefore ,
There is no change in csa .
Zero percent change in csa.
New volume ( V ) = π× (2r)² × ( h / 2 )
= 2πr²h
= 2 × v
Therefore ,change in volume is
100%
I hope this helps you.
:)
1) Dimensions of the cylinder
radius = r
Height = h
i ) curved surface area
(CSA) = 2πrh----( 1 )
ii ) volume (v) = πr² h ---( 2 )
2 ) if radius doubled and radius
halved then new cylinder
dimensions are
Radius ( R ) = 2r
Height ( H ) = h /2
New CSA = 2 × π × ( 2r ) × h / 2
= 2πrh
Therefore ,
There is no change in csa .
Zero percent change in csa.
New volume ( V ) = π× (2r)² × ( h / 2 )
= 2πr²h
= 2 × v
Therefore ,change in volume is
100%
I hope this helps you.
:)
Answered by
7
Answer:
the change in volume is 100%
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