Math, asked by saratkumarsahu282, 19 days ago

If in a long division sum, the dividend is 380606 and the successive remainders from the first to the last are 434, 125 and 413, then the divisor is :

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Answered by polinati

If In A Long Division Sum,the Dividend Is 380606 And The Successive Remainders From The First To The Last Are 434, 125 And 413, Then The Divisor Is? d x q = 380193.

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If in a long division sum, the dividend is 380606 and the successive remainders from the first to the last are 434, 125 and 413, then the divisor is : ​

Answers

If in a long division sum, the dividend is 380606 and the successive remainders from the first to the last are 434, 125 and 413, then the divisor is :