Question

If in a parallelogram angle A is 2x+3 and angle D is x-3 and AB is parallel to CD then angle B is

Answer 1

Answer:

Step-by-step explanation:

2x+3 + x-3 = 180°

3x = 180°

x = 60

i.e angle A = 123°

then angle B = 180° - 123 = 57°

Answer 2

Answer:

$\bold\red{Angle\:B=57°}$

Step-by-step explanation:

Given,

in the parallelogram ABCD,

angle A = (2x +3)

angle A = (2x +3)angle D = (x -3)

Also,

AB parallel to CD

and ,

AD will be transversal

Therefore,

angle A and angle D are co-interior angles.

therefore,

angle A + angle D = 180

=> 2x + 3 + x -3 = 180

=> 3x = 180

=> x = 60

Therefore,

angle A = 2×60 +3 = 123°.

angle D = 60 - 3 = 57°

Now,

BC parallel to CD

and

AB is a transversal

Therefore,

angle A and angle B are co-interior angles

Therefore,

angle A + angle B = 180

=> angle B + 123 = 180

=> angle B = 57°

Hence,

Angle B = 57°