If in a progression the sum of n terms is 5n2 +3n, find 5th term of it.
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Putting n=1, 5n²-3n
=5-3=2
Putting n=2, 5n²-3n
=14
Therefore 2nd term is 14-2=12
Therefore AP is 2, 12, 22 ... and so on.
10th term=a+9d
=2+9*10
=2+90
=92
durgeshsinghrajput30:
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a th term can be found as
: Sn - S(n-1)
a5=S5 - S4
= 5(5)2+3(5) - {5(4)2+3(4)}
=50+15-(40+12)
=65-52
=13
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