Math, asked by radicaltiger, 8 months ago

if in a quadrilateral abcd, AC perpendicular to BD and AC and BD bisecta each other then prove it is a rhombus

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Answered by aj0360121

Answer:

Sol: We have a quadrilateral ABCD such that the diagonals AC and BD bisect each other at right angles at O. Their corresponding parts are equal. Thus, the quadrilateral ABCD is a rhombus

Step-by-step explanation:

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if in a quadrilateral abcd, AC perpendicular to BD and AC and BD bisecta each other then prove it is a rhombus​

Answers

if in a quadrilateral abcd, AC perpendicular to BD and AC and BD bisecta each other then prove it is a rhombus