Math, asked by trisha0704delhi, 16 hours ago

if in a quadrilateral, angle a = 90°, angle b = 48 °, angle d = 161° and angle c = 61° then angle adc = ?

Attachments:

Answers

Answered by Biswabibhusita
0

Answer:

Extend AB and CD to intersect at O

Now ∠AOD=90

°

because given ∠A+∠D=90

°

Applying right angled triangle rules ;

⇒AC

2

=OA

2

+OC

2

and ⇒BD

2

=OB

2

+OD

2

Adding both equations ;

⇒AC

2

+BD

2

=(OA

2

+OD

2

)+(OB

2

+OC

2

)

⇒AC

2

+BD

2

=AD

2

+BC

2

Answered by jyotimurmu722
1

Answer:

The measure of angle adc is 161°.

Step-by-step explanation:

As said angle d is equal to 161°

therefore, angle adc equals to 161°.

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