If in a reaction HNO3 is reduced to NO, the mass of HNO3 absorbing 1 mole of
electron would be
a) 12.6gm (6) 21 gm (c) 31.5 gm (d) 63.0 gm
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We have HNO3---->NO
The change in oxidation number is +3
Equivalent mass of HNO3 =(1+14+16+16+16+16)/3=63/3
=2l g (around
Hence, Option (b) is answer.
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