If in a rhombus XYZW, XZ = 24 cm and YW = 23 cm, then find out the area of the rhombus.Required to answer. Single choice.
276 cm²
250 cm²
275 cm²
66,
Answers
Answer:
276 cm^2
Step-by-step explanation:
MARK ME BRAINLIST
Answer:
The area of the rhombus is 276 cm².
Step-by-step-explanation:
NOTE: Refer to the attachment for the diagram.
In figure, □XYZW is a rhombus.
Seg XZ & seg YW are diagonals of the rhombus.
XZ = 24 cm
YW = 23 cm
We have to find the area of the rhombus.
Now, we know that,
Area of rhombus = ( Product of diagonals ) / 2
⇒ A ( □XYZW ) = ( XZ * YW ) / 2
⇒ A ( □XYZW ) = ( 24 * 23 ) / 2
⇒ A ( □XYZW ) = 552 ÷ 2
⇒ A ( □XYZW ) = 276 cm²
∴ The area of the rhombus is 276 cm².
───────────────────────
Additional Information:
1. Rhombus:
A quadrilateral with all of its four sides of equal measures is called as rhombus.
2. Properties of Rhombus:
1. All sides are congruent.
2. Opposite angles are congruent.
3. Diagonals bisect each other.
4. Diagonals are perpendicular bisectors of each other.
3. Perimeter of Rhombus:
The sum of the lengths of the all sides of the rhombus is the perimeter of the rhombus.
- Perimeter of rhombus = 4 * side
4. Area of Rhombus:
The surface bounded by the rhombus is called its area.
- Area of rhombus = ( Product of diagonals ) / 2
