if in a right angle triangle abc angle B is a right angle then find the value of sin A cos c
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Step-by-step explanation:
Given in △ ABC, ∠B=90
o
.
This given A+C=180
o
−90
o
=90
o
......(1).
Now,
sinA.cosC+cosA.sinC
=sin(A+C)
=sin(90
o
)
=1.
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