Math, asked by AkiraNishizawa, 1 year ago

If in a right angled triangle ABC, AB= 3cm, AC= 4cm and BC= 5cm then the radius of the incircle of triangle ABC will be what?

Answers

Answered by prithuchauhan22
11

For a right triangle ,

Radius of incircle = a+b-c/2 where C is the hypotenuse. Hence the answer is 3+4-5/2 = 2/2 =1 cm

Answered by Syamkumarr
0

Answer:

Radius of the circle = 1 cm    

Step-by-step explanation:

Given data

sides of right angle triangle in a incircle of the triangle are

⇒ AB = 3 cm, BC = 5 cm and AC = 4 cm  

⇒ here the longest side is BC is the hypotenuse and  AB and AC are the base and height of the triangle

⇒ in a incircle of right angle triangle  

⇒ Radius of the circle

      r = Area of the triangle / semi perimeter of the triangle  

⇒ Area of triangle = (base × height)/ 2 =  3 × 4 / 2 = 12/2 = 6 cm

⇒ semi perimeter  of triangle = (AB+BC+AC )/ 2

                                                  (3+4+5) / 2 = 12/ 2 =6  

⇒ radius of the circle = 6/6 = 1 cm    

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