if in a right angled triangle ABC <b=90° BC=7cm , AC-ab = 1cm , then find the value of sin A and cos A
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Hey friend, Here is your answer.
O.S. = Opposite Side
A.S. = Adjacent side
Sin A = BC / AC
= 7 / 25
Cos A = AB / AC
= 24 / 25
Hope it will help you.
please Please make me brainliest.
O.S. = Opposite Side
A.S. = Adjacent side
Sin A = BC / AC
= 7 / 25
Cos A = AB / AC
= 24 / 25
Hope it will help you.
please Please make me brainliest.
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