If in a right angled triangle: Angle A = 45°, Angle B = 90° , Angle C = 45°, prove that sin B = 1.
Note : This question is not in any book. It suddenly came in my mind. Can anyone give me an appropriate reason that why the answer of this question is not coming?
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Answer:
sin B=SIN90=1
Step-by-step explanation:
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Answered by
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Step-by-step explanation:
sinB = p/h
Because here, perpendicular tends to become equal to hypotenuse as angle approaches 90°(You can see it by drawing a triangle with any angle and then try to make it 90°)
Therefore, sin90°=1
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