Math, asked by aaditya200614, 3 months ago

If in a right angled triangle: Angle A = 45°, Angle B = 90° , Angle C = 45°, prove that sin B = 1.








Note : This question is not in any book. It suddenly came in my mind. Can anyone give me an appropriate reason that why the answer of this question is not coming?​

Answers

Answered by piyushprajapatiop
0

Answer:

sin B=SIN90=1

Step-by-step explanation:

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Answered by usernametaken8
0

Step-by-step explanation:

sinB = p/h

Because here, perpendicular tends to become equal to hypotenuse as angle approaches 90°(You can see it by drawing a triangle with any angle and then try to make it 90°)

Therefore, sin90°=1

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