If in a right angled triangle triangle abc tan b =12/5 then find the value of sin b
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Answered by
17
Answer:
SinB=5/13
Step-by-step explanation:
Since 2 sides of this right angled triangle are 5 and 12,third side is 13 by Pythagoras rule a^2+b^2=c^2
Here B was the angle opposite the 12cm side so longest side is hypotenuse or 13cm
Therefore CosB becomes
5/13
Answered by
7
Answer:
since 2 sides of this right angled triangle are 5 and 12,third side is 13 by Pythagoras rule a^2+b^2=c^2
here b was the angle opposite the 12 cm side so longest side is hypotenuse or 13cm
therefore cos b becomes
5/13
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