Math, asked by harivermasharma3476, 9 months ago

If in a right angled triangle triangle abc tan b =12/5 then find the value of sin b

Answers

Answered by acv49
17

Answer:

SinB=5/13

Step-by-step explanation:

Since 2 sides of this right angled triangle are 5 and 12,third side is 13 by Pythagoras rule a^2+b^2=c^2

Here B was the angle opposite the 12cm side so longest side is hypotenuse or 13cm

Therefore CosB becomes

5/13

Answered by manikandrkulamani
7

Answer:

since 2 sides of this right angled triangle are 5 and 12,third side is 13 by Pythagoras rule a^2+b^2=c^2

here b was the angle opposite the 12 cm side so longest side is hypotenuse or 13cm

therefore cos b becomes

5/13

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