Question

If in a right triangle RPQ, right angled at P, QR =26cm and QP=24 cm,then the length of PR is: *​

Answer 1

given;

∆ RPQ is right angle triangle

where ,

QR= 26cm and QP=24cm

to find;

the length og PR

now

by Pythagoras theorem

$qr ^{2} = pq ^{2} + rp ^{2} \\ \\( 26) ^{2} = (24) ^{2} + pr ^{2} \\ \\ 676 = 576 + pr ^{2} \\ \\ 676 - 576 = pr ^{2} \\ \\ pr = \sqrt{100} \\ pr = 10$

hence proved , pr=10 cm

Answer 2

Given :-

• Lenght of QR = 26 cm

• Lenght of QP = 24 cm

• Right angled at P

To Find :-

• Lenght of PR

Solution :-

By using Pythagoras theorem

★ ( PR )² + ( QP )² = ( QR )²

⇒ ( PR )² + ( 24 )² = ( 26 )²

⇒ ( PR )² + 576 = 676

⇒ ( PR )² = 676 - 576

⇒ ( PR )² = 100

⇒ PR = √100

⇒ PR = 10 cm

Lenght of PR us 10 cm