If in a square ABCD ,AB =(2x+3)cm and BC =(3x-5) cm ,find BD. [HINT: BD SQUARE =AB SQUARE+AD SQUARE by pythagoras theorem, AD=BC].
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BD²=AB²+BC² (as BD=AC)
BD²=(2x+3)²+(3x-5)²
BD²=4x²+12x+9+9x²-30x+25
BD²=13x²-18x+34
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