if in a square ABCD ,AC=(7x-2) and BD=11x-10 findAC?
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Answered by
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In a square AC and BD are diagonals hence they are equal
So
[tex]7x-2 = 11x-10 8 = 4x x = 2[/tex]
It is given that
![AC = 7x-2 = (7*2)-2 = 12 AC = 7x-2 = (7*2)-2 = 12](https://tex.z-dn.net/?f=AC+%3D+7x-2+%3D+%287%2A2%29-2+%3D+12)
So
[tex]7x-2 = 11x-10 8 = 4x x = 2[/tex]
It is given that
leenjossan:
thanx
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