Question

If in a traingle ABC sines of angles A and B satisfies the equation 4x2 -2
$\sqrt{6}$
x +1=0, then
cos (A-B)=
b) 1/2
c) 1/2
d) 3/2 16 ]
a) 0​

Answer 1

Step-by-step explanation:

Sum of roots 

sinA+

sinB

 

=

c

a+b

=

sinC

sinA+sinB

sin(A)+

sin(B)[1−

sinC

1

]=

0

sinC=

1

C=

90

0

.

Hence,

sinA+

cosA

=

sinA+

sinB

=

a

asinA

+

b

bsinB

=

c

sinC(a+b)

=

c

a+b

=

c

a+b

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