Question

if in a triangle abc angle A = 71 degree and perpendicular from vertex B and C on the opposite side intersect at point P find the angle BPC​

Answer 1

Answer:

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Step-by-step explanation:

I have turned the triangle in the second pic to show you how triangle inequality worked...

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Answer 2

Angle BPC=109 degrees

Step-by-step explanation:

In triangle ABC

$\angle A=71^{\circ}$

Let the perpendicular drawn from vertex B intersect AC at point F and the perpendicular drawn from vertex C and intersect AB at point E.

Angle AEP=Angle AFP=90 degrees

In quadrilateral AEPF

Angle A+angle AEP+angle AFP+angle EPF=360 degrees

Sum of angles of quadrilateral =360 degrees

Substitute the values then we get

$71+90+90+\angle EPF=360$

$251+\angle EPF=360$

$\angle EPF=109^{\circ}$

Angle EPF=Angle BPC

Vertical angles are equal

Angle BPC=109 degrees

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