if in a triangle abc angle A + angle b is equal to 108 degree and Angle B + c is equals to 130 degree find all three angles
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12
given a+b=108
and b+c=130
so .we know that a+b+c=180
putting the values of a,b,c in above eqn we get
108-b+b+130-b=180
238-b=180
so.b=238-180=58
a=108-b=50
and c=180-108=72
and b+c=130
so .we know that a+b+c=180
putting the values of a,b,c in above eqn we get
108-b+b+130-b=180
238-b=180
so.b=238-180=58
a=108-b=50
and c=180-108=72
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