Math, asked by putulrakshit, 10 months ago

If in a triangle ABC, angle ABC+angle ACB=90 degree. Prove that CA is perpendicular to AB​

Answers

Answered by suhanisaxena112
3

Answer:your answer is below in the pic

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Answered by lublana
0

Answer with Step-by-step explanation:

Given

\angle ABC+\angle ACB=90^{\circ}

In triangle ABC

\angle ABC+\angle ACB+\angle BAC=180^{\circ}

By using triangle angles sum property

Substitute the values then we get

90+\angle BAC=180

\angle BAC=180-90

By using subtraction property of equality

\angle BAC=90^{\circ}

When the angle between two sides is equal to 90 degrees then the two sides are perpendicular.

Therefore, CA is perpendicular to AB.

Hence, proved.

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https://brainly.in/question/11497987

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